You May Be a Winner: Enter Now!
April 5, 2011
Dear Kay, and potential Mitered Crosses Blanket Makers of the World,
I GOT LUCKY! I mean, I WON SOMETHING.
Last week I was down at lush ‘n’ lovely Bliss Yarns, foraging for Silk Garden and generally glad to see everybody there. They were having a contest where you guess the number of M & Ms in a sizeable jar. I did my Supersecret Trick* for estimating small things that are put into large containers, and BINGO:
I won! How fun is that? Really fun:
Two dozen balls of lush, plummy yarn, and beautiful needles, and patterns. Thank you, Bliss! It made my day.
It was so fun, in fact, that I really want to share this sensation of good luck with somebody out there. I’ve decided to turn my prize into a door prize for our mighty Mitered Crosses Blanket project.
Here’s the deal: now that so many of you have bought this pattern, we would like to encourage you to cast on your blankets, mostly because we hate to knit alone, and we believe that knitting blankets in groups is one of the highest forms of human interaction.
Also: it’s so fun to see what yarns everybody is using–already there are 120+ unique projects over there. Check them out.
So, get your pattern here. Head over to Ravelry, create a new Mitered Crosses project in your Notebook, and post a photo of your fledgling Mitered Crosses Blanket. If you don’t know how to do this, here’s a tutorial on adding a new project to your Ravelry Notebook.
We’ll draw a random winner from all the Mitered Crosses Blankets that have been listed as started on Ravelry, including the blankets begun before this contest began.
Deadline for posting your new project on Ravelry: Friday, April 8, 8:08 pm CDT. We’ll announce the winner as soon as possible after then.
I am happy to report that Kay just sent off another batch of dollars to Mercy Corps, thanks to all you wonderful knitters who have supported Japan relief efforts by buying the Mitered Crosses Blanket pattern. To date: $8,500 total.
Have fun! Knit often! Remember, all it takes is a square and a dream.
*OK, here’s my Supersecret Estimating Trick, revealed once and for all. Works every time! Use it in good health!
where the sum is over the nontrivial zeros of the zeta function and where Π0 is a slightly modified version of Π that replaces its value at its points of discontinuity by the average of its upper and lower limits.